Kahibaro
Discord Login Register

Time Course of Chemical Reactions

What Does “Time Course” of a Reaction Mean?

When chemists talk about the time course of a chemical reaction, they mean how the amounts (or concentrations) of reactants and products change as time passes. Instead of only asking “What are the starting materials and final products?”, kinetics asks:

To describe and measure this systematically, we use:

In this chapter, we focus on how these quantities behave over time, without yet going deeply into temperature effects or catalysis (covered in later chapters).

Reaction Rate as a Function of Time

For a general reaction

$$
\text{a A} + \text{b B} \rightarrow \text{c C} + \text{d D}
$$

we define the instantaneous rate at a certain time $t$ via the change in concentration with time:

$$
v(t) = -\frac{1}{a} \frac{d[\text{A}]}{dt}
= -\frac{1}{b} \frac{d[\text{B}]}{dt}
= \frac{1}{c} \frac{d[\text{C}]}{dt}
= \frac{1}{d} \frac{d[\text{D}]}{dt}
$$

Key points for the time course:

On a concentration–time graph:

Experimental Observation of the Time Course

To follow the time course, chemists monitor some observable quantity that depends on concentration:

Experimental procedure (conceptual):

  1. Mix reactants quickly to define $t = 0$.
  2. Measure an observable quantity at defined times.
  3. Convert observables into concentrations (using calibration or known relations).
  4. Plot concentration vs. time and analyze the curve.

The resulting curves show the time course directly.

Rate Laws and Their Consequences for Time Course

For many reactions, the rate law has a simple power-law form. For a reaction involving one reactant A,

$$
v(t) = -\frac{d[\text{A}]}{dt} = k \,[\text{A}]^{n}
$$

Different orders produce characteristic concentration–time curves. Understanding these shapes is central to describing the time course.

We will look qualitatively at zero-, first-, and second-order behavior, which are commonly encountered ideal cases.

Zero-Order Reactions

Rate law:

$$
-\frac{d[\text{A}]}{dt} = k
$$

Integration gives:

$$
\text{A} = [\text{A}]_0 - kt
$$

where $[\text{A}]_0$ is the initial concentration at $t = 0$.

Time course characteristics:

Zero-order behavior can appear when a surface or catalyst is saturated, so that the limiting factor is not how much A is left in solution.

First-Order Reactions

Rate law:

$$
-\frac{d[\text{A}]}{dt} = k\,[\text{A}]
$$

Integration gives:

$$
\text{A} = [\text{A}]_0\, e^{-kt}
$$

This is an exponential decay.

Half-Life for First-Order Reactions

The half-life $t_{1/2}$ is the time required for the concentration to drop to half its initial value:

$$
\text{A} = \frac{1}{2} [\text{A}]_0
$$

Insert into the integrated law:

$$
\frac{1}{2} [\text{A}]_0 = [\text{A}]_0 e^{-kt_{1/2}}
\Rightarrow e^{-kt_{1/2}} = \frac{1}{2}
\Rightarrow t_{1/2} = \frac{\ln 2}{k}
$$

Important property:

Time course characteristics:

Many processes such as radioactive decay and some simple decompositions follow first-order kinetics.

Second-Order Reactions (Simple Cases)

Consider a simple second-order case with only one reactant A:

$$
-\frac{d[\text{A}]}{dt} = k\,[\text{A}]^2
$$

Integration gives:

$$
\frac{1}{\text{A}} = \frac{1}{[\text{A}]_0} + kt
$$

Time course characteristics:

The half-life now depends on the initial concentration:

$$
t_{1/2} = \frac{1}{k\,[\text{A}]_0}
$$

Another common second-order situation: reaction of two different species with equal initial concentrations:

$$
\text{A} + \text{B} \rightarrow \text{Products}, \quad [\text{A}]_0 = [\text{B}]_0
$$

This often shows a similar integrated form and similar time-course behavior (fast initial decay that slows markedly with time).

Initial Rate and Early-Time Behavior

The initial rate $v_0$ is the rate very near $t = 0$. It is often easier to measure accurately because:

For many rate laws, the early-time behavior can be approximated by:

$$
v_0 = v(t \approx 0) = k \, f([\text{A}]_0, [\text{B}]_0, \dots)
$$

where $f$ expresses the dependence on initial concentrations (e.g., $f = [\text{A}]_0^n$).

The slope at the very beginning of a concentration–time curve equals the initial rate. The shape just after $t = 0$ gives information on the order and mechanism.

Typical Shapes of Concentration–Time Curves

For a single reactant A converting to products:

For products, the curves usually show the complementary, increasing trends, often approaching a plateau when reactants are depleted (or when equilibrium is reached in reversible systems).

Time Course in Reversible Reactions (Qualitative)

For a reversible reaction

$$
\text{A} \rightleftharpoons \text{B}
$$

there are forward and reverse rates:

Typical time course:

  1. At $t = 0$, only A present: forward rate is high, reverse rate is zero.
  2. As B forms, reverse rate increases; forward rate decreases as A is consumed.
  3. Eventually, forward and reverse rates become equal: the system reaches dynamic equilibrium.
  4. Concentrations then remain constant over time (though both directions continue at equal rates).

On a concentration–time plot:

The detailed connection between time course and equilibrium constants is treated in the chapters on chemical equilibrium and the law of mass action; here we only note that reversible reactions often show a characteristic approach to constant concentrations.

Pseudo-Order and Its Effect on Time Course

In many practical cases, several reactants are involved, but one is in large excess. For example:

$$
\text{A} + \text{B} \rightarrow \text{Products}, \quad [\text{B}]_0 \gg [\text{A}]_0
$$

The rate law might be:

$$
v = k\,[\text{A}][\text{B}]
$$

If $[\text{B}]$ remains approximately constant over the time of interest (because B is in huge excess), we can define an effective rate constant:

$$
k' = k [\text{B}] \approx \text{const.}
$$

and write:

$$
v = k' [\text{A}]
$$

So although the true reaction is second order, the observed time course of $[\text{A}]$ behaves like a first-order reaction (this is called pseudo-first-order behavior).

Time-course consequence:

This trick is widely used to simplify kinetic analysis: by using large excess of one reactant, the time course becomes easier to interpret and model.

Relating Time Course and Mechanism (Qualitative)

The way concentrations change with time often gives clues about the reaction mechanism (the sequence of elementary steps).

Some qualitative examples:

Even without doing full mathematical treatments, recognizing such shapes in concentration–time plots helps infer possible mechanisms.

Summary: Key Ideas for the Time Course of Reactions

Views: 24

Comments

Please login to add a comment.

Don't have an account? Register now!