Kahibaro
Discord Login Register

Standard Redox Potentials and Redox Equilibria

Standard Redox Potentials: Definition and Meaning

In earlier chapters, redox reactions were introduced as electron transfer processes and described using oxidation numbers and balanced equations. To compare how “strong” different oxidizing and reducing agents are, chemists use standard redox potentials.

A redox (electrode) potential describes the tendency of a chemical species to be reduced (gain electrons) relative to a reference system. Under standard conditions

the potential of a half-reaction is called the standard redox potential and is written as $E^\circ$.

Conventionally, all half-reactions are written as reductions, for example:

$$
\ce{Cu^{2+} + 2 e^- -> Cu}
$$

The corresponding standard potential is written as $E^\circ(\ce{Cu^{2+}/Cu})$.

Reference Electrode: Standard Hydrogen Electrode (SHE)

To have a common scale, all half-cell potentials are measured relative to a defined reference: the standard hydrogen electrode (SHE).

All other $E^\circ$ values are measured against the SHE and placed on a redox series or electrochemical series.

Sign and Magnitude of $E^\circ$

For a half-reaction written as a reduction:

Example values (approximate):

The more positive the potential of a half-reaction, the more readily it proceeds as written (as a reduction) under standard conditions.

Comparing Redox Couples and Predicting Reaction Direction

For a complete redox reaction, two half-reactions are combined:

To predict which direction is favored under standard conditions:

  1. Write the two possible reduction half-reactions with their $E^\circ$ values.
  2. The species with the more positive $E^\circ$ will preferentially be reduced.
  3. The other half-reaction will run in reverse and serve as the oxidation.

Example: Zinc and Copper(II)

Half-reactions (as reductions):

Since copper’s $E^\circ$ is more positive, $\ce{Cu^{2+}}$ is reduced, and zinc must be oxidized:

Oxidation (reverse of the tabulated reduction):
$$
\ce{Zn -> Zn^{2+} + 2 e^-}
$$

Overall redox reaction:
$$
\ce{Zn + Cu^{2+} -> Zn^{2+} + Cu}
$$

This prediction matches the observation that zinc metal can displace copper from $\ce{Cu^{2+}}$ solutions.

Calculating Standard Cell Potentials

A complete electrochemical cell consists of two half-cells:

The standard cell potential $E^\circ_{\text{cell}}$ under standard conditions is:

$$
E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}}
$$

Here, $E^\circ_{\text{cathode}}$ and $E^\circ_{\text{anode}}$ are the standard potentials of the half-reactions written as reductions.

Example: Zn–Cu Cell

Cathode (reduction):
$$
\ce{Cu^{2+} + 2 e^- -> Cu}, \quad E^\circ_{\text{cathode}} = +0.34\,\mathrm{V}
$$

Anode (oxidation, but tabulated as reduction):
$$
\ce{Zn^{2+} + 2 e^- -> Zn}, \quad E^\circ_{\text{anode (as red.)}} = -0.76\,\mathrm{V}
$$

Then:
$$
E^\circ_{\text{cell}} = (+0.34\,\mathrm{V}) - (-0.76\,\mathrm{V}) = +1.10\,\mathrm{V}
$$

Notes:

Redox Equilibria and the Nernst Equation

For non-standard conditions, the actual cell potential $E$ differs from $E^\circ$. The relationship between potential, concentrations, and reaction quotient $Q$ is given by the Nernst equation.

For a general redox half-reaction:

$$
\ce{Ox + n e^- <=> Red}
$$

the Nernst equation for the half-cell potential (at $25^\circ\mathrm{C}$) is:

$$
E = E^\circ - \frac{0.059\,\mathrm{V}}{n} \log_{10} \left( \frac{[\ce{Red}]}{[\ce{Ox}]} \right)
$$

More generally (for any temperature):

$$
E = E^\circ - \frac{RT}{nF} \ln \left( \frac{a(\ce{Red})}{a(\ce{Ox})} \right)
$$

with:

For a complete cell reaction with $n$ transferred electrons and overall reaction quotient $Q$:

$$
E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{0.059\,\mathrm{V}}{n} \log_{10} Q
$$

Reaction Quotient $Q$ for Redox Reactions

$Q$ is formed from the activities (or approximate concentrations) of the reaction products divided by the reactants, each raised to the power of their stoichiometric coefficients.

Example for
$$
\ce{Zn + Cu^{2+} <=> Zn^{2+} + Cu}
$$

Solids (Zn, Cu) have activity ≈ 1 and do not appear in $Q$. Thus:

$$
Q = \frac{a(\ce{Zn^{2+}})}{a(\ce{Cu^{2+}})} \approx \frac{[\ce{Zn^{2+}}]}{[\ce{Cu^{2+}}]}
$$

The Nernst equation then links $E_{\text{cell}}$ to the ratio of $\ce{Zn^{2+}}$ and $\ce{Cu^{2+}}$ concentrations.

Connection Between Standard Potentials and Equilibrium Constants

At equilibrium, the net cell reaction no longer proceeds in any direction on the macroscopic scale, and the cell potential is zero:

$$
E_{\text{cell}} = 0
$$

At the same time, the reaction quotient becomes the equilibrium constant $K$.

Inserting $E_{\text{cell}} = 0$ and $Q = K$ into the Nernst equation for the overall cell gives:

$$
0 = E^\circ_{\text{cell}} - \frac{0.059\,\mathrm{V}}{n} \log_{10} K
$$

Rearranged:

$$
E^\circ_{\text{cell}} = \frac{0.059\,\mathrm{V}}{n} \log_{10} K
$$

or equivalently:

$$
\log_{10} K = \frac{n\,E^\circ_{\text{cell}}}{0.059\,\mathrm{V}}
$$

This shows:

This provides a quantitative bridge between electrochemical data and the position of chemical equilibrium.

Spontaneity and Direction of Redox Equilibria

Standard redox potentials can be used to judge:

Procedure:

  1. Identify the two redox couples.
  2. Look up their $E^\circ$ (as reductions).
  3. The couple with the higher $E^\circ$ is reduced; the other is oxidized.
  4. Compute $E^\circ_{\text{cell}}$ and, if needed, the corresponding equilibrium constant $K$.

If $E^\circ_{\text{cell}} > 0$, the reaction is spontaneous in the direction written (toward products) under standard conditions, and the equilibrium lies on the product side. If $E^\circ_{\text{cell}} < 0$, the equilibrium is shifted toward the reactants; the reverse reaction is spontaneous.

In this way, standard redox potentials serve both as a scale of oxidizing/reducing strength and as a tool for understanding and quantifying redox equilibria.

Views: 28

Comments

Please login to add a comment.

Don't have an account? Register now!