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Applications of Integrals

Using Integrals to Measure and Accumulate

Indefinite and definite integrals give us a way to describe how quantities accumulate. In this chapter we focus on what you can do with integrals: how they measure area, volume, total change, and many other “totals” built from rates or densities.

You should already be familiar with the idea of a definite integral as a limit of Riemann sums and with basic computation of integrals. Here we concentrate on interpreting integrals in real-world and geometric situations.

General Interpretation: Integral as Accumulated Quantity

Many applications share a common pattern:

If $x$ is a variable (time, length, etc.) and $f(x)$ is a rate or density (per unit of $x$), then the total accumulated quantity from $x = a$ to $x = b$ is
$$
\int_a^b f(x)\,dx.
$$

You can think of $f(x)\,dx$ as the contribution from a tiny piece of width $dx$. The integral adds up all those tiny contributions.

Common language pairs:

We now examine two of the most important geometric applications: area in the plane and volume of solids.

Area Between Curves

You already know that if $f(x) \ge 0$ on $[a,b]$, then the definite integral
$$
\int_a^b f(x)\,dx
$$
represents the (signed) area under the graph of $f$ and above the $x$–axis. We now extend this to the area between two curves.

Area Between a Top and Bottom Function

Suppose on the interval $[a,b]$:

Then the area of the region bounded vertically by $y=f(x)$ and $y=g(x)$, and between $x=a$ and $x=b$, is
$$
A = \int_a^b \bigl[f(x) - g(x)\bigr]\,dx.
$$

Reasoning: For each small strip of width $dx$, the height is “top minus bottom” $f(x)-g(x)$, so area of the thin strip is $(f(x)-g(x))\,dx$. The integral adds all these strip areas from $a$ to $b$.

Finding the Limits of Integration

In many problems, the intersection points of the curves become the limits of integration. You often:

  1. Solve $f(x) = g(x)$ to find intersection $x$–values.
  2. Check which function is on top between those intersections.
  3. Integrate top minus bottom.

If the order of top/bottom changes on the interval, you must:

Area with Respect to $y$ (Horizontal Strips)

Sometimes curves are more easily described as $x$ as a function of $y$ (i.e., $x = f(y)$). Then the region may be bounded by a right curve and a left curve.

If:

then the area is
$$
A = \int_c^d \bigl[ R(y) - L(y) \bigr]\,dy.
$$

Here, each horizontal strip has height $dy$ and length $R(y)-L(y)$.

Working with $y$ instead of $x$ is especially useful when:

Volumes of Solids of Revolution

Integrals also allow us to compute volumes of many three-dimensional shapes, especially those obtained by revolving a region around an axis. The general strategy is to slice the solid into many thin pieces, find the volume of a typical slice, and integrate.

There are three main methods you will encounter:

Each method corresponds to a different way of slicing the solid.

Disk Method (No Hollow Core)

Use the disk method when revolving a region that touches the axis of rotation, so the cross-sections perpendicular to the axis are solid disks.

Revolving Around the $x$–Axis

Suppose $y = f(x) \ge 0$ on $[a,b]$, and the region between the curve and the $x$–axis is revolved around the $x$–axis. The resulting solid has cross-sections perpendicular to the $x$–axis that are circles (disks).

At position $x$:

The volume is
$$
V = \int_a^b \pi [f(x)]^2\,dx.
$$

Revolving Around the $y$–Axis

If instead you have $x = g(y) \ge 0$ for $y$ in $[c,d]$ and revolve the region between this curve and the $y$–axis around the $y$–axis, then the cross-sectional disks are perpendicular to the $y$–axis:

At height $y$:

so
$$
V = \int_c^d \pi [g(y)]^2\,dy.
$$

Washer Method (Hollow Core)

Use the washer method when the region being revolved does not touch the axis of rotation, creating a hole in the middle, like a washer (a disk with a circular hole).

The cross-section perpendicular to the axis is now an annulus (ring). Each washer is described by:

Area of a washer:
$$
\text{Area} = \pi R^2 - \pi r^2 = \pi\bigl(R^2 - r^2\bigr).
$$

Revolving Around the $x$–Axis

Suppose the region between $y = f(x)$ and $y = g(x)$ on $[a,b]$ is revolved around the $x$–axis, with $f(x)$ farther from the $x$–axis than $g(x)$ (so $f(x) \ge g(x) \ge 0$):

Then the volume is
$$
V = \int_a^b \pi\bigl(R(x)^2 - r(x)^2\bigr)\,dx
= \int_a^b \pi\bigl(f(x)^2 - g(x)^2\bigr)\,dx.
$$

Similarly, for revolution around the $y$–axis, you express radii in terms of $y$ and integrate with respect to $y$.

Shell Method (Cylindrical Shells)

With the disk or washer method, slices are perpendicular to the axis of rotation. The shell method uses slices that are parallel to the axis, forming cylindrical shells when revolved.

A typical shell:

If you unroll a thin cylindrical shell, its lateral surface area is approximately
$$
\text{Lateral area} \approx 2\pi r \cdot h.
$$
Multiplying by the shell thickness gives the shell volume:
$$
dV \approx 2\pi r h \, (\text{thickness}).
$$

Shell Method Around the $y$–Axis (Integrate with Respect to $x$)

Consider a region between $x = a$ and $x = b$, bounded above and below by $y$–values, and revolve it around the $y$–axis.

Take a vertical strip at position $x$ (width $dx$). When revolved about the $y$–axis, this strip generates a cylindrical shell.

Then the volume is
$$
V = \int_a^b 2\pi r(x) h(x)\,dx.
$$

In many problems, $h(x)$ is “top function minus bottom function” in $y$:
$$
h(x) = f(x) - g(x),
$$
so
$$
V = \int_a^b 2\pi x\,[f(x) - g(x)]\,dx.
$$

Shell Method Around the $x$–Axis (Integrate with Respect to $y$)

If you revolve a region around the $x$–axis and you prefer to integrate with respect to $y$, you use horizontal strips of thickness $dy$.

At height $y$:

Then
$$
V = \int_c^d 2\pi r(y) h(y)\,dy = \int_c^d 2\pi y\,h(y)\,dy.
$$

Choosing Between Disk/Washer and Shell

Often both methods are theoretically possible; one will be easier.

Typical preferences:

Choose the direction of slicing that:

Physical and Real-World Accumulations

The same logic behind area and volume extends to many physical contexts. The pattern is always:

Total quantity $= \int$ (density or rate) $\times$ (small piece).

Here are some common types.

Total Change from a Rate

If $r(t)$ is the rate of change of some quantity $Q$ with respect to time (for example, velocity, flow rate, production rate), then the net change in $Q$ from $t=a$ to $t=b$ is
$$
\Delta Q = \int_a^b r(t)\,dt.
$$

If $Q(a)$ is known, you get
$$
Q(b) = Q(a) + \int_a^b r(t)\,dt.
$$

Examples include:

Accumulating Density over a Line

Suppose a thin rod lies along the $x$–axis from $x=a$ to $x=b$, and its linear density (mass per unit length) is $\lambda(x)$ (for example, in kg/m). A tiny piece of length $dx$ at position $x$ has mass approximately $\lambda(x)\,dx$.

The total mass is
$$
M = \int_a^b \lambda(x)\,dx.
$$

Analogously:

Density over an Area or Volume

In higher dimensions:

These are examples of multiple integrals, which you will study more fully in multivariable calculus, but the underlying idea is the same: integrate density over the region.

Work Done by a Variable Force (Preview)

If a force $F(x)$ acts along a line and can vary with position, then the work done in moving an object from $x=a$ to $x=b$ is
$$
W = \int_a^b F(x)\,dx.
$$

This fits the pattern “work $=$ force $\times$ distance,” with force varying over distance.

In other contexts, a similar integral describes:

These topics are typically developed further in more advanced courses or chapters, but the integral concept is the same.

Summary

Later topics will extend these ideas to more dimensions and more complex settings, but the fundamental interpretation of the integral as an accumulator remains the same.

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